Questions
Time period of oscillation of a simple pendulum on the surface of earth is T. At what height above the surface of earth will the time period be 4T ?
a
3R2
b
R
c
3R
d
2R
detailed solution
Correct option is C
T=2πlg and 4T=2πlg' ∴ T4T=g'g = RR+h ⇒ h=3RTalk to our academic expert!
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