Questions
Time period of a particle executing SHM is 8 s. At t = 0, it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2nd second is
detailed solution
Correct option is D
Here x=Asinωtx1=Asin2π8×1=Asinπ4=A2 and x2=Asin2π8×2=ATherefore, the distance traveled in 2nd second isx2′=x2−x1=A−A2=(2−1)A2∴ Ratio =x1x2′=A/2(2−1)A2=1(2−1) =2+1(2−1)(2+1)=(2+1)2−1=(2+1)Talk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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