Time period of a particle executing SHM is 8 s. At t = 0, it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2nd second is

Here x=Asin⁡ωtx1=Asin⁡2π8×1=Asin⁡π4=A2 and  x2=Asin⁡2π8×2=ATherefore, the distance traveled in 2nd second isx2′=x2−x1=A−A2=(2−1)A2∴  Ratio =x1x2′=A/2(2−1)A2=1(2−1) =2+1(2−1)(2+1)=(2+1)2−1=(2+1)