Questions
The time period of a simple pendulum inside a stationary lift is sec. What will be the time period when the lift moves upward with an acceleration g/4?
detailed solution
Correct option is D
time period of a simple pendulum is T=2πlg ----(1)and time period of a simple pendulum in a lift accelerating upward is T1=2πl(g+a)⇒ T1=2πl(g+g/4) ⇒T1=2πl(5g/4)---(2) divide equation (1) by (2) ⇒ TT1=54 ⇒T1=2T5, by question T=5, substitute in above equation ⇒T1=2 secondsTalk to our academic expert!
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A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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