Questions
The time period of a simple pendulum inside a stationary lift is sec. What will be the time period when the lift moves upward with an acceleration g/4?
detailed solution
Correct option is D
In upward accelerating lift, geff = g + a T=2πlg and T1=2πl(g+g/4) ⇒T1T=25 given T=5 ⇒T1=25T=255 ⇒T1=2 secondsTalk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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