The time period of a simple pendulum inside a stationary lift is 5sec. What will be the time period when the lift moves upward with an acceleration g/4?
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a
5seconds
b
25seconds
c
2+5seconds
d
2 seconds
answer is D.
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Detailed Solution
In upward accelerating lift, geff = g + a T=2πlg and T1=2πl(g+g/4) ⇒T1T=25 given T=5 ⇒T1=25T=255 ⇒T1=2 seconds