Questions
The time period of simple pendulum of length l as measured in an elevator descending with acceleration g/3 is
detailed solution
Correct option is C
When the elevator is descending, thenmg−T=ma or T=m(g−a)∴ t=2πlg−aGiven that a = g /3∴ t=2πlg−(g/3)=2π3l2gTalk to our academic expert!
Similar Questions
A truck is stationary and has a bob suspended by a light string, in a frame attached to the truck. The truck, suddenly moves to the right with an acceleration of a. The pendulum will tilt
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