Q.

The time period of a simple pendulum in a lift descending with constant acceleration g is

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a

T=2πlg

b

T=2πl2g

c

Zero

d

Infinite

answer is D.

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Detailed Solution

This is the case of freely falling lift and in free fall of lift effective g for pendulum will be zero. So T=2πlg-a=2πl0=∞∵a=g
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