Questions
The time period of a simple pendulum in a lift descending with constant acceleration g is
a
T=2πlg
b
T=2πl2g
c
Zero
d
Infinite
detailed solution
Correct option is D
This is the case of freely falling lift and in free fall of lift effective g for pendulum will be zero. So T=2πlg-a=2πl0=∞∵a=gTalk to our academic expert!
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A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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