The time period of simple pendulum is ‘T’ when the length increases by 20cm, its period is T1. When the length is decreased by 20 cm, its time period is T2. When the relation between T,T1 and T2 is
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a
2T2=1T12+1T22
b
2T2=1T12−1T22
c
2T2=T12+T22
d
2T2=T12−T22
answer is C.
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Detailed Solution
time period of a simple pendulum is T=2πlg here 2π, g are constant Tαl on squaring, kT2=l-----(1) kT12=l+20---(2) kT22=l-20---(3) add equation (2)and (3) k(T12+T22)=2l---(4) substitute l from equation (1) k(T12+T22)=2(kT2) T12+T22=2T2