First slide

Simple hormonic motion

Question

Time period of a spring mass system is T. If this spring is cut into two parts whose lengths are in the ratio 1 : 3 and the some mass is attached to the longer part, the new time period will be :

Easy

A

$\sqrt{\frac{3}{2}} T$
B

$\frac{T}{\sqrt{3}}$
C

$\frac{\sqrt{3} T}{2}$
D

$\sqrt{3} T$

Solution

For spring kl= constant so spring constant of longer part $k' = \frac{4}{3} k .$
But $T \propto \frac{1}{\sqrt{k}} so T' = \frac{\sqrt{3}}{2} T .$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App