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Q.

Time period (T) and amplitude (A) are same for two particles which undergo SHM along the same line. At one particular instant, one particle is at phase 3π2 and other is at phase zero. While moving in the same direction. Find the time at which they will cross each other:

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a

4T/2

b

3T/8

c

3T/4

d

3T/7

answer is B.

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Detailed Solution

At phase 3π/2,(ωt+ϕ)=3π/2                  x1=Asin⁡3π2=−Ax2=0 So, at t=0,x1=−Acos⁡ωt and x2=Asin⁡ωtx1=x2−cos⁡ωt=sin⁡ωt⇒tan⁡ωt=−1ωt=3π4⇒2πTt=3π4  or  t=3T/8
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