At time t = 0, a car moving along a straight line has a velocity of 16 ms-1. It slows down with an acceleration of -0.5t ms-2, where t is in seconds. Mark the correct statement(s).

This is the example of non-uniform acceleration. a=dvdt=−0.5t∫16v dv=−∫0t 0.5tdt⇒v=16−0.5t22Direction of velocity changes at the moment when it becomes zero momentarily. 0=16−0.5t22⇒t=8sdxdt=v=16−0.5t22Let us consider that at t = 0, particle is at x = 0∫0x dx=∫0t 16−0.5t22; x=16t−0.5t36Distance travelled =∣displacement∣ for t≤8 s. So, distance travelled in 4 sx=16×4−0.5×436≃59mDistance travelled in 10 s=∣ Displacement in 8s∣×2− Displacement in 10s=85.33×2−76.66=94mv(t=10s)=−9ms−1