At time t $$=$$ $$0$$, one particle is at maximum positive amplitude and the other particle is at half of the positive amplitude. Their amplitudes and time periods T are same. If they are approaching, find the time by which they cross each other:

Question

Infinity Learn · Accepted Answer

$$x1=$$ A $$cos$$ ωt (at$$ t $$=$$ $$0$$, $$x1$$ $$=$$ $$A)x2$$ $$=$$ A $$sin$$$$($$ω$$t+$$π$$6)              (at$$ t $$=0$$, $$x2$$ $$=$$ $$+A2)For$$ $$x1$$ $$=$$ $$x2$$, $$cos$$ ωt $$=$$ $$sin$$ $$($$ω$$t+$$π$$6)     $$=$$ $$sin$$ ωt $$cos$$ π$$6+$$$$cos$$ ωt $$sin$$ π$$6cos$$ ω$$t(1-$$$$sin$$$$π$$$$6)$$ $$=$$ $$sin$$ ωt $$cos$$ π$$6tan$$ ωt $$=$$ (1-$$$$sin$$$$π$$$$6)$$cos$$ π$$6$$ $$=$$ $$13$$ωt $$=$$ $$(2$$$$π$$$$T)t$$ $$=$$ π$$6Will$$ give t $$=$$ $$T12$$

At time t = 0, one particle is at maximum positive amplitude and the other particle is at half of the positive amplitude. Their amplitudes and time periods T are same. If they are approaching, find the time by which they cross each other:

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