The time taken by a particle executing SHM of period T to move from the extreme position to half the maximum displacement is
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a
T3
b
T4
c
T8
d
T6
answer is D.
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Detailed Solution
For a particle executing simple harmonic motion starting from extreme position, the equation for displacement is y=Acosωt i.e., A2=Acos2πTt . On simplifying this we get 12=cos2πTt. To satisfy this condition, π3=2πTt , i.e. T6=t