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The time taken by a particle executing SHM of period T to move from the extreme  position to half the maximum displacement is

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a
T3
b
T4
c
T8
d
T6

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detailed solution

Correct option is D

For a particle executing simple harmonic motion starting from extreme position,  the equation for displacement is  y=Acosωt   i.e., A2=Acos2πTt . On simplifying this we get  12=cos2πTt. To satisfy this condition, π3=2πTt , i.e.  T6=t


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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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