The time taken by a particle executing simple harmonic motion to pass from point A to B where its velocities are same, is 2 s. After another 2 s, it returns to b. The time period of oscillation is
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a
2 s
b
4 s
c
6 s
d
8 s
answer is D.
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Detailed Solution
The situation is illustrated in Fig.t2-t1= 2 s, t3-t2=2 s i.e., t3-t1=4 s which is half of the time period. So, T = 8s
The time taken by a particle executing simple harmonic motion to pass from point A to B where its velocities are same, is 2 s. After another 2 s, it returns to b. The time period of oscillation is