First slide

Electrical power

Question

Time taken by a 896 W heater to heat one litre of water from 10°C to 40°C is

Moderate

A

50 s
B

100 s
C

150 s
D

200 s

Solution

Let t, be the time taken- Then
$\begin{array}{l} 836 \times t = 1 \times (4 \cdot 2 \times 10^{3}) \times (40 - 10) \\ t = \frac{30 \times (4 \cdot 2 \times 10^{3})}{836} \approx 150 s \end{array}$

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