A tiny spherical oil drop of radius r carrying a net charge q is balanced in still air with a vertical uniform electric field of strength E. When the field is switched off, the drop is observed to fall with terminal velocity v , viscosity of the air =η and the density of oil = d. The magnitude of q is
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a
q=6ηrvπE
b
q=πηrv6E
c
q=6πηrEv
d
q=6πηrvE
answer is D.
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Detailed Solution
In equilibrium, mg = qE ----(1)In the absence of electric field, mg=6πηrv----(2) qE=6πηrv⇒q=6πηrvE