A toroidal solenoid has 3000 turns and a mean radius of 10 cm. It has a soft iron core of relative permeability 2000. What is the magnitude of the magnetic field in the core when a current of 1 amp is passed through the solenoid ?
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a
0.12 T
b
0.24 T
c
1.2 T
d
12 T
answer is D.
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Detailed Solution
The magnetic field in the core is Biven by B = μni where n = number of turns per unit length of the solenoid.∴B=μ0μrni ∵μr=μ/μ0 or B=2000×4π×10−7×30002π×0⋅1×1=12T