Q.
A total charge Q is broken in two parts Q1 and Q2 and they are placed at a distance R from each other. The maximum force of repulsion between them will occur, when
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a
Q2=QR, Q1=Q−QR
b
Q2=Q4, Q1=Q−2Q3
c
Q2=Q4, Q1=3Q4
d
Q1=Q2, Q2=Q2
answer is D.
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Detailed Solution
Q1+Q2=Q ….(i) and F=kQ1Q2r2 ….(ii)From (i) and (ii) F=kQ1(Q−Q1)r2For F to be maximum dFdQ=0⇒Q1=Q2=Q2
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