The total energy of the body executing S.H.M. is E. Then the kinetic energy when the displacement is half of the amplitude, is

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3E4

34E

answer is C.

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Detailed Solution

Total energy in SHM E=12mω2a2 ; (where a = amplitude)Potential energy KE=12mω2(a2−y2) U=12mω2y2When y=a2 ⇒KE=E−U KE = E-12mω2a24=E−E4=3E4

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