Questions
The total energy of the body executing S.H.M. is E. Then the kinetic energy when the displacement is half of the amplitude, is
a
E2
b
E4
c
3E4
d
34E
detailed solution
Correct option is C
Total energy in SHM E=12mω2a2 ; (where a = amplitude)Potential energy KE=12mω2(a2−y2) U=12mω2y2When y=a2 ⇒KE=E−U KE = E-12mω2a24=E−E4=3E4Talk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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