Questions
The total energy of a body executing SHM is E. Then the kinetic energy when its distance from equilibrium position is half of the amplitude, is
a
E/2
b
E/4
c
3E/4
d
3E4
detailed solution
Correct option is C
E=12mA2ω2Now, KE=12mA2ω21−x2A2When x=A2, KE=E1−A/22A2=3E4Talk to our academic expert!
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