Q.

The total energy of a body executing SHM is E. Then the kinetic energy when its distance from equilibrium position is half of the amplitude, is

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a

E/2

b

E/4

c

3E/4

d

3E4

answer is C.

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Detailed Solution

E=12mA2ω2Now,  KE=12mA2ω21−x2A2When x=A2, KE=E1−A/22A2=3E4
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