Q.
The total energy of a body executing SHM is E. Then the kinetic energy when its distance from equilibrium position is half of the amplitude, is
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a
E/2
b
E/4
c
3E/4
d
3E4
answer is C.
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Detailed Solution
E=12mA2ω2Now, KE=12mA2ω21−x2A2When x=A2, KE=E1−A/22A2=3E4
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