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Q.

The total energy of the electron in the first excited state of hydrogen is - 3.4 eV. What is the kinetic energy of the electron (in eV) in this state?

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answer is 3.4.

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Detailed Solution

As KEn=−TEn⇒KE=+3.4eV

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The total energy of the electron in the first excited state of hydrogen is - 3.4 eV. What is the kinetic energy of the electron (in eV) in this state?