The total energy of an electron in the $n^{th}$ stationary orbit of the hydrogen atom can be obtained by

• A

  ${\mathrm{E}}_{\mathrm{n}}=-13.6\times {\mathrm{n}}^2\mathrm{eV}$

• B

  ${\mathrm{E}}_{\mathrm{n}}=\frac{13.6}{{\mathrm{n}}^2}\mathrm{eV}$

• C

  ${\mathrm{E}}_{\mathrm{n}}=-\frac{13.6}{{\mathrm{n}}^2}\mathrm{eV}$

• D

  ${\mathrm{E}}_{\mathrm{n}}=-\frac{1.36}{{\mathrm{n}}^2}\mathrm{eV}$