The total energy of a particle executing SHM is 48 Joule. Then find its potential energy when its displacement is half of the amplitude.

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8 J

24 J

16 J

12 J

answer is D.

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Detailed Solution

E = Total Energy =12 mω2 A2∴ 12 mω2 =E/ A2Now, U = Potential Energy 12 mω2 x2When x=A2, U=EA2 × A22=E4=484 J=12J.

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