The total energy of a particle, executing simple harmonic motion is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
∝x
b
∝x2
c
∝x1/2
d
independent of x
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
, In simple harmonic motion, the total energy E is given byE= P.E. + K.E. =12mω2x2+12mω2a2−x2 =12mω2a2 =12m(2πn)2a2=2π2mn2a2 This is independent of displacement x