Questions
The total energy of a particle, executing simple harmonic motion is
a
∝x
b
∝x2
c
∝x1/2
d
independent of x
detailed solution
Correct option is D
, In simple harmonic motion, the total energy E is given byE= P.E. + K.E. =12mω2x2+12mω2a2−x2 =12mω2a2 =12m(2πn)2a2=2π2mn2a2 This is independent of displacement xTalk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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