Questions
Total energy of particle performing SHM depends on
detailed solution
Correct option is A
total energy =12k A2 k = mω2= propogation constant A = amplitude ω = 2πT T=time period total energy = 12mωA2 TE=12m2πT2A2 TE depends on mass of oscillator, Time period, Amplitude of oscillatorSimilar Questions
When the displacement is half the amplitude, the ratio of potential energy to the total energy is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests