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The total energy of a vibrating particle in S.H.M is E. If it’s amplitude and time period are doubled, it’s total energy will be

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a
16 E
b
8 E
c
4 E
d
E

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detailed solution

Correct option is D

total energy of a vibrating particle E=12mw2A2 E=12m2πT2A2---(1) new time period T1=2T and amplitude A1=2A new energy of vibrating particle =E1=12m2πT12A12 substitute given values E1=12m2π2T2(2A)2 E1=12m2πT2A2 substitute eqn (1) E1=E


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