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Q.

The total energy of a vibrating particle in S.H.M is E. If it’s amplitude is tripled and time period are doubled, it’s total energy will be

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a

16 E

b

8 E

c

4 E

d

94E

answer is D.

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Detailed Solution

As  E=12mw2A2, mass of oscillator=m, angular velocity=w, Amplitude=AE=12m2πT2A2-----(1)As new time period  T1=2T, new amplitude  A1=3A, substitute in new energy E1∴E1=12m2π2T2×(3A)2E1=12m×142πT2×9A2------(2)From (1) and (2),  E1=94E
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