The total energy of a vibrating particle in S.H.M is E. If it’s amplitude is tripled and time period are doubled, it’s total energy will be
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a
16 E
b
8 E
c
4 E
d
94E
answer is D.
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Detailed Solution
As E=12mw2A2, mass of oscillator=m, angular velocity=w, Amplitude=AE=12m2πT2A2-----(1)As new time period T1=2T, new amplitude A1=3A, substitute in new energy E1∴E1=12m2π2T2×(3A)2E1=12m×142πT2×9A2------(2)From (1) and (2), E1=94E