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Q.

The total length of a sonometer wire between fixed ends is 110 cm. Two bridges are placed to divide the length of wire in ratio 6 : 3 : 2. The tension in the wire is 400 N and the mass per unit length is 0.01 kg/m. What is the minimum common frequency with which three parts can vibrate?

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a

166 Hz

b

1000 Hz

c

500 Hz

d

1100 Hz

answer is A.

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Detailed Solution

Frequency of transverse oscillation in a stretched string fixed at both ends is given byNowSo fundamental frequency of string (l) is the minimum common frequency of oscillation. nmin=12lmaxTμ=
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