The total mechanical energy of a harmonic oscillator of amplitude 1 m and force constant 200 N/m is 150 J then

detailed solution

Correct option is C

equation for Kinetic energy KE is,                           KE=12kA2-x2, here k= force constant, A= amplitude,x=displacement at x=0, KE is maximum,KEmax=12kA2,now substitute given values of k and A                                                KEmax=12×200×12                                            ⇒KEmax=100 J                                                       TE=KEmax+PEmin                                                      150=100+PEmin                                             ⇒PEmin=50 J