Questions
The total mechanical energy of a harmonic oscillator of amplitude 1 m and force constant 200 N/m is 150 J then
detailed solution
Correct option is C
equation for Kinetic energy KE is, KE=12kA2-x2, here k= force constant, A= amplitude,x=displacement at x=0, KE is maximum,KEmax=12kA2,now substitute given values of k and A KEmax=12×200×12 ⇒KEmax=100 J TE=KEmax+PEmin 150=100+PEmin ⇒PEmin=50 JSimilar Questions
When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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