Questions
The total mechanical energy of a harmonic oscillator of amplitude 1 m and force constant 200 N/m is 100 J then
detailed solution
Correct option is A
given force constant k=200N/mtotal energy TE=100 Jmaximum kinetic energy is KE =12mw2A2 maximum kinetic energy KE=12kA2 maximum kinetic energy KE=12×200×12 ∴KEmax=100 JTotal energy TE=KEmax+PEmin100=100+PEminPEmin=0 JSimilar Questions
When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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