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Questions  

The total mechanical energy of a particle executing simple harmonic motion is E. When the displacement is half the amplitude its kinetic energy will be

a
3E4
b
E
c
E2
d
E4

detailed solution

Correct option is A

E = 12mω2A2   and K.E = 12mω2(A2-x2)Putting x= A2 or x2 = A44K.E. = 12mω2(A2-A24) = 34[12mω2A2] = 3E4

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