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The total number of degrees of freedom of molecules of hydrogen of volume 1 cc at NTP is $1.34 \times 10^{(5 \times N)}$ . Find N.

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Solution

1 mole of hydrogen at NTP occupies 22.4 litres.
Therefore, number of moles in 1 cc of hydrogen at NTP = $\frac{1}{22.4 \times 1000} (1) = 4.46 \times 10^{- 5}$
Number of molecules of Hydrogen = $(4.46 \times 10^{- 5}) (6.023 \times 10^{23}) = 26.86 \times 10^{18}$
Each hydrogen molecule has 5 degrees of freedom.
So, total number of degrees of freedom = $5 \times 26.86 \times 10^{18} = 1.34 \times 10^{20}$

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Internal energy

Remember concepts with our Masterclasses.

The total number of degrees of freedom of molecules of hydrogen of volume 1 cc at NTP is 1.34×10(5×N). Find N.

Ready to Test Your Skills?

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The total number of degrees of freedom of molecules of hydrogen of volume 1 cc at NTP is $1.34 \times 10^{(5 \times N)}$ . Find N.