Questions
The total power content of AM wave is 1320 W. The percentage modulation if each side band contains 160 W is
detailed solution
Correct option is D
PT=1320 W We know, 12PSB=PLSB and 12PSB=PUSB ∴PSB=2PLSB=2×160 = 320 W Also , PT=Pc+PSB ⇒1320=Pc+320 ⇒Pc=1000 W Now, PTPc=1+m22 ⇒13201000=1+m22 ⇒1.32=1+m22 ⇒0.32=m22 ⇒m2 = 0.64 ⇒m=0.8 i.em%=m×100=0.8×100= 80%Talk to our academic expert!
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A message signal of frequency 10 kHz and peak voltage of 10 volts is used to modulate a carrier of frequency 1 MHz and peak voltage of 20 volts. The side bands are 1010 kHz and______________kHz.
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