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Questions  

For traffic moving at 60 km/ hour along a circular track of radius 0⋅1 km, the correct angle of banking is

a
(60)2/0⋅1km
b
tan−1⁡(50/3)2100×9⋅8
c
tan−1⁡100×9⋅8(50/3)2
d
tan−1⁡(60×0⋅1×9⋅8)

detailed solution

Correct option is B

θ=tan−1⁡v2rgHere         v=60×10360×60=(50/3)r=0⋅1km=100m  and  g=9⋅8m/sec2∴ θ=tan−1⁡(50/3)2100×9.8

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