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Questions  

For traffic moving at 60 km/hr along a circular track of radius 0⋅1 km, the correct angle of banking is

a
tan−1⁡6020⋅1
b
tan−1⁡(50/3)2100×9⋅8
c
tan−1⁡(60×0⋅1×9⋅8)1/2
d
tan−1⁡100×9⋅8(50/3)2

detailed solution

Correct option is B

We know that,     tan⁡θ=v2rg∴ Î¸=tan−1⁡v2rgGiven that,    v=60km/hr=60×10360×60m/secr=0⋅1km=100m  and  g=9⋅8m/sec2∴ Î¸=tan−1⁡(50/3)2100×9⋅8

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