For traffic moving at 60 km/hr along a circular track of radius 0â 1 km, the correct angle of banking is
tanâ1â¡6020â 1
tanâ1â¡(50/3)2100Ã9â 8
tanâ1â¡(60Ã0â 1Ã9â 8)1/2
tanâ1â¡100Ã9â 8(50/3)2
We know that, tanâ¡Î¸=v2rg
ⴠθ=tanâ1â¡v2rg
Given that, v=60km/hr=60Ã10360Ã60m/sec
r=0â 1km=100m and g=9â 8m/sec2
ⴠθ=tanâ1â¡(50/3)2100Ã9â 8