A train of mass M is moving on a circular track of radius R with constant speed v. The length of train is half the perimeter of track. The linear momentum of the train will be
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a
0
b
2Mv/π
c
MvR
d
Mv
answer is B.
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Detailed Solution
Total momentum =∫θ=−90+90 (dm)vcosθdm=MπR×RdθTotal momentum =∫MπRvRdθcosθ=2Mvπ