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Q.

A train of mass M is moving on a circular track of radius R with constant speed v. The length of train is half the perimeter of track. The linear momentum of the train will be

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a

0

b

2Mv/π

c

MvR

d

Mv

answer is B.

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Detailed Solution

Total momentum =∫θ=−90+90 (dm)vcos⁡θdm=MπR×RdθTotal momentum =∫MπRvRdθcos⁡θ=2Mvπ
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