Q.
A train of mass M is moving on a circular track of radius R with constant speed v. The length of the train is half of the perimeter of the track. The linear momentum of the train will be
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a
πMv
b
2Mvπ
c
πMv2
d
Mv
answer is B.
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Detailed Solution
pnet =∫dp sinθ=∫0πMπ·dθv· sinθ=2Mvπ
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