Q.

A train of mass M is moving on a circular track of radius R with constant speed v. The length of the train is half of the perimeter of the track. The linear momentum of the train will be

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a

πMv

b

2Mvπ

c

πMv2

d

Mv

answer is B.

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Detailed Solution

pnet =∫dp sinθ=∫0πMπ·dθv· sinθ=2Mvπ
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