A train moving with a speed of 60 km/hr is slowed down uniformly to 30 km/hr for repair purposes during running. After this it was accelerated uniformly to reach to its original speed. If the distance covered during constant retardation be 2 km and that covered during constant acceleration be 1 km, find the time lost in the above journey.

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Detailed Solution

Time taken by train in retardationBy using s=u+v2t ⇒2=60+302t1⇒t1=245hrTime taken by train in accelerated motionBy using u+v2t ⇒1=30+602t2⇒t2=145hTime taken by train to travel 3 km by uniform motiont3=360=120hrTime lost = 345−120×60=1min

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