Q.

A train passes through a station with a constant speed. A stationary observer at the station platform measures the tone of the train whistle as 484 Hz when it approaches the station and  442 Hz when it leaves the station. If the sound velocity in air is  330m/s, then the tone of the whistle and the speed of the train are

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

462 Hz,54 km/h

b

468 Hz,72 km/h

c

463 Hz,56 km/h

d

472 Hz,63 km/h

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

When train approaches the station, the frequency heard by the observerυ1=υvv−vs=υ330330−vsHere,  v=330 m/sυ is the actual frequency of the whistle484=υ330330−vs.....1When the train leaves the stationυ2=υvv+vs=υ330330+vs....2Divide Equations (1) & (2), we get⇒484442=330+vs330−vs⇒1.09=330+vs330−vs⇒vs=31.352.09=15 m/s=15 ×185=54kmphSubstituting  vs in equation gives⇒484=υ330330−15=υ330315⇒υ=484×2122∴υ=462 HzTherefore, the correct answer is (A).
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon