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Q.

A train is passing by a platform at a constant speed of 40 m/s. The train horn is sounded at a frequency of 378 Hz. Find the overall change in frequency as detected by a person standing on the platform, as the train moves from approaching to receding. (Take velocity of sound in air as 320 m/s)

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a

104 Hz

b

92 Hz

c

84 Hz

d

96 Hz

answer is D.

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Detailed Solution

For situation l, fap1 = v-0v-vs×f                          = 320320-40×378 = 432 Hz For situation 2, fap2 = vv-(-vS)×f = 336 Hzf =fap1-fap2 = 96 Hz
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