A train stopping at two stations 4 km apart takes 4 min on the journey from one of the station to the other. Assuming that it first accelerates with a uniform acceleration x and then that of uniform retardation y, then.
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a
1x+1y=8
b
1x+1y=4
c
1x+1y=2
d
1x+1y=6
answer is C.
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Detailed Solution
v0t1=x⇒t1=v0x v0t2=y⇒t2=v0y t1+t2=v01x+1y=A ----(i)Further,area = displacement12v0×t=sBut numerically, t=s=4 units v0=2 units Substituting in eq (i) we get,1x+1y=2