The transfer characteristic curve of a transistor, having input and output resistance 100 Ω and 100 k Ω respectively, is shown in the figure. The power gain is p×106. Find the value of p.
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answer is 2.50.
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Detailed Solution
Current Gain=β=ΔicΔib=(10−5)×10−3(200−100)×10−6=50Voltage gain =βR2R1=50×100×103100=50×103Power Gain=Voltage gain×Current Gain=50×103×50=2.5×106