First slide

Transistors

Question

The transfer ratio of the transistor is 50. The input resistance of the transistor when used in the CE configuration is 1 k $Ω$ . The peak value for an AC input voltage of 0.01 V of collector current is

Moderate

A

$500 μA$
B

0.25 mA
C

400 mA
D

0.01 mA

Solution

Given, $β = 50, R_{i} = 1000 Ω, V_{i} = 0 .01 V$
$β = \frac{I_{C}}{I_{B}}$ ………(i)
and $I_{B} = \frac{V_{i}}{R_{i}} = \frac{0 .01}{10^{3}} = 10^{- 5} A$
$I_{C} = 50 \times 10^{- 5} A = 500 μA$ [from Eq. (i)]

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