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Q.

The transfer ratio of the transistor is 50. The input resistance of the transistor when used in the CE configuration is 1 kΩ. The peak value for an AC input voltage of 0.01 V of collector current is

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a

500μA

b

0.25 mA

c

400 mA

d

0.01 mA

answer is A.

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Detailed Solution

Given, β=50,Ri=1000Ω,Vi=0.01V β=ICIB ………(i)and IB=ViRi=0.01103=10−5A IC=50×10−5A=500μA [from Eq. (i)]

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