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Questions  

The transfer ratio of the transistor is 50. The input resistance of the transistor when used in the CE configuration is 1 kΩ. The peak value for an AC input voltage of 0.01 V of collector current is 

a
500μA
b
0.25 mA
c
400 mA
d
0.01 mA

detailed solution

Correct option is A

Given, β=50,Ri=1000Ω,Vi=0.01V             β=ICIB   ………(i)and  IB=ViRi=0.01103=10−5A         IC=50×10−5A=500μA  [from Eq. (i)]

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