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Q.

A transformer has 100 turns in the primary coil and carries 8 A current. If input power is one kilowatt, the number of turns required in the secondary coil to have 500V output will be

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a

100

b

200

c

400

d

300

answer is C.

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Detailed Solution

Ps=Vsis⇒1000=Vs×8⇒Vs=10008VpVs=NpNs⇒(1000/8)500=100Ns⇒Ns=400
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