First slide

Electrical machines and devices

Question

A transformer has 100 turns in the primary coil and carries 8 A current. If input power is one kilowatt, the number of turns required in the secondary coil to have 500V output will be

Moderate

A

100
B

200
C

400
D

300

Solution

$\begin{array}{l} P_{s} = V_{s} i_{s} \Rightarrow 1000 = V_{s} \times 8 \Rightarrow V_{s} = \frac{1000}{8} \\ \frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}} \Rightarrow \frac{(1000 / 8)}{500} = \frac{100}{N_{s}} \Rightarrow N_{s} = 400 \end{array}$

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