First slide

Electrical machines and devices

Question

In a transformer, the number of turns in primary and secondary are 500 and 2000 respectively. If current in primary is 48 A, the current in the secondary is

Moderate

A

12 A
B

24 A
C

48 A
D

144 A

Solution

$\frac{N_{s}}{N_{p}} = \frac{i_{p}}{i_{s}} \Rightarrow \frac{2000}{500} = \frac{48}{i_{s}} \Rightarrow i_{s} = 12 A$

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