First slide

Electrical machines and devices

Question

In a transformer the primary has 500 turns and secondary has 50 turns. 100 volts are applied to the primary coil, the voltage developed in the secondary will be

Moderate

A

1 V
B

10 V
C

1000 V
D

10000 V

Solution

$\frac{N_{S}}{N_{P}} = \frac{V_{S}}{V_{P}} \frac{50}{500} = \frac{V_{S}}{100} V_{S} = 10 V$

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