A transformer with efficiency 80% works at 4 kW and 100 V. If the secondary voltage is 200 V, then the primary and secondary currents are respectively

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40 A, 16 A

16 A, 40 A

20 A, 40 A

40 A, 20 A

answer is A.

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Detailed Solution

η= output power input power =EsIsEpIp⇒80100=200×Is4×103⇒IS=80100×4×1000200=16A Also, EpIp=4KW⇒Ip=4×103100=40A

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