First slide

Transistors

Question

For a transistor amplifier in common emitter configuration for load impedance of $1 k Ω$ ( $h_{f e} = 50$ and $h_{o e} = 25 μ A / v$ ) the current gain is

Very difficult

A

-5.2
B

-15.7
C

-24.8
D

-48.78

Solution

For a transistor amplifier in common emitter configuration, current gain
$A_{i} = \frac{- h_{f e}}{1 + h_{o e} R_{L}}$
Where $h_{f e} = 50$ and $h_{o e} = 25 μ A / v$ are hybrid parameters of a transistor.

$∴ A_{i} = \frac{- 50}{1 + 25 \times 10^{- 6} \times 1 \times 10^{3}} = - \frac{50}{1 + 25 \times 10^{- 3}} = \frac{- 50}{1 + \frac{25}{1000}} = - \frac{50}{1 + 0.025} = - \frac{50}{1.025} = - 48.78$

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