First slide

Transistors

Question

In a transistor, a change of 5mA in the emitter current produces a change of 4.95mA in the collector current. The base current changes by

Easy

A

25µA
B

50µA
C

75µA
D

100µA

Solution

$W e k n o w, I_{E} = I_{B} + I_{C}$
$\Rightarrow Δ I_{E} = Δ I_{B} + Δ I_{C}$
$\Rightarrow 5 = Δ I_{B} + 4.95$
$\Rightarrow Δ I_{B} = 0.05 m A = 50 x 10^{- 6} A = 50 µ A$

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