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Q.

In a transistor circuit, the base current changes from 30  μA  to  90  μA. If the current gain of the transistor is 30, the change in emitter current is

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a

1.60 mA

b

0.96 mA

c

1.22 mA

d

1.86 mA

answer is D.

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Detailed Solution

(4)ΔICΔIB=β  ⇒   ΔIC90−30=30   ⇒  ΔIC=1800  μA=1.8  mA∴   ΔIE  =  ΔIC +  ΔIB=1800  μA+60μA=1.86  mA
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