First slide

Transistors

Question

A transistor is connected in CE configuration. The collector supply in 8V and the voltage drop across a resistor of $800 Ω$ in the collector circuit is 0.5 V. If $α = 0.96$ , then the base current is $x μ A$ . Find $x$

Difficult

Solution

$R e l a t i o n b e t w e e n β a n d α$
$β = \frac{α}{1 - α} = \frac{0.96}{1 - 0.96} = 24$
$T h e c o l l e c t o r c u r r e n t i s, I_{C} = \frac{V_{C}}{R} = \frac{0.5}{800} = 6.25 \times 10^{- 4} A &$
$R a t i o β = \frac{I_{c}}{I_{B}} ⇒ I_{B} = \frac{I_{c}}{β} = \frac{6.25 \times 10^{- 4}}{24} = 26 \times 10^{- 6} A = 26 μ A$

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